RFLP Method - Restriction Fragment Length Polymorphism

In the segement of DNA shown below, you can see the elements of an RFLP; a target sequence flanked by a pair of restriction sites. When this segment of DNA is cut by EcoR I, three restriction fragments are produced, but only one contains the target sequence which can be bound by the complementary probe sequence (purple).

Let's look at two people and the segments of DNA they carry that contain this RFLP (for clarity, we will only see one of the two stands of DNA). Since Jack and Jill are both diploid organisms, they have two copies of this RFLP. When we examine one copy from Jack and one copy from Jill, we see that they are identical:

Jack 1: -GAATTC---(8.2 kb)---GCATGCATGCATGCATGCAT---(4.2 kb)---GAATTC-

Jill 1: -GAATTC---(8.2 kb)---GCATGCATGCATGCATGCAT---(4.2 kb)---GAATTC-

When we examine their second copies of this RFLP, we see that they are not identical. Jack 2 lacks an EcoR I restriction site that Jill has 1.2 kb upstream of the target sequence (difference in italics).

Jack 2: -GAATTC--(1.8 kb)-CCCTTT--(1.2 kb)--GCATGCATGCATGCATGCAT--(1.3 kb)-GAATTC-

Jill 2: -GAATTC--(1.8 kb)-GAATTC--(1.2 kb)--GCATGCATGCATGCATGCAT--(1.3 kb)-GAATTC-

Therefore, when Jack and Jill have their DNA subject to RFLP analysis, they will have one band in common and one band that does not match the other's in molecular weight:

paternity Case

Let's use RFLP technology to determine if Jack is the father of Jill's child named Payle.

In this scenario, DNA was extracted from white blood cells from all three individuals and subjected to RFLP analysis. The results are shown below:

In this case, it appears that Jack could be the father, since Payle inherited the 12.4 kb fragment from Jill and the 4.3 fragment from Jack. However, it is possible that another man with similar RFLP pattern could be as well.To be certain, several more RFLP loci would be tested. It would be highly unlikely that two men (other than identical twins) would share multiple RFLP patterns and so paternity could be confirmed.

In a different scenario, DNA was extracted from white blood cells from all three individuals and subjected to RFLP analysis. The results are shown below:

This time, it can be determined that Jack is NOT the father of Payle since Payle has a band of about 6 kb and Jack does not. Therefore, it is very probable that Payle's father is not Jack, though it is possible that Payle carries a new mutation at this locus and a different sized band was produced. What could you do as an investigator to be more certain that Jack was not the father of Payle?

Disease Status

In this example, we want to know if a person carries any cystic fibrosis (CF) alleles and if so, how many. Because CF is a recessive disease, anyonne with CF must be homozygous for disease alleles. From pedigree information, we can often determine who in this family is a carrier. However, if a couple comes to a genetic counselor, often an RFLP analysis is performed on the couple's DNA.

RFLPs are known for CF and so it would be easy to determine if a person were homozygous wild-type (wt), heterozygous "carrier", or homozygous disease alleles and thus have CF.

For couples expecting a child, it would be simple to test both parents and make a prediction about the eventual disease status of their fetus. For example, if both parents were homozygous wt, then all of their children would also be homozygous wt:

However, if both parents were heterozygous, they could have children with any of the three genotypes, though heterozygous children would be twice as likely as either of the homozygous genotypes.

With increasing genomic sequence information, increasing numbers of genetic disease can be predicted from RFLP analyses.

Genetic Mapping

To calculate the genetic distance between to loci, you need to be able to observe recombination. Traditionally, this was performed by observing phenotypes but with RFLP analysis, it is possible to measure the genetic distance between two RFLP loci whether they are a part of genes or not.

Let's look at a simple example in fruit flies. Two RFLP loci with two RFLP bands possible at each locus:

These loci are located on the same chromosome for the female (left) and the male (right). The upper locus can produce two different bands called 1 and 3. The lower locus can produce bands called 2 or 4. The male is homozygous for band 1 at the upper locus and 2 for the lower locus. The female is heterozygous at both loci. Thier RFLP banding patterns can be seen on the Southern blot below:

The male can only produce one type of gamete (1 and 2) but the female can produce four different gametes. Two of the possible four are called parental because they carry both RFLP bands from the same chromosome; 1 and 2 from the left chromosome or 3 and 4 from the right chromosome. The other two chromosomes are recombinant because recombination has occurred between the two loci and thus the RFLP bands are mixed so that 1 is now linked to 4 and 3 is linked to 2.

When these two flies mate, the frequency of the four possible progeny can be measured and from this information, the genetic distance between the two RFLP loci (upper and lower) can be determined.

In this example, 70% of the progeny were produce from parental genotype eggs and 30% were produced by recombinant genotype eggs. Therefore, these two RFLP loci are 30 centiMorgans apart from each other.